@King said:

In reply to: https://mathstodon.xyz/users/axiom/statuses/100538817825750480

🐴 [7. Be2] ♗ c4 → e2

@robert's turn

Sun, 12 Aug 2018 19:03:35 GMT

FEN: r1bqkb1r/ppp1n1pp/5p2/n3p3/4P3/5N1P/PPPPBPP1/RNBQK2R b KQkq - 2 7

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